-16x^2+18x+49=0

Solution for -16x^2+18x+49=0 equation:

-16x^2+18x+49=0

a = -16; b = 18; c = +49;
Δ = b2-4ac
Δ = 182-4·(-16)·49
Δ = 3460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3460}=\sqrt{4*865}=\sqrt{4}*\sqrt{865}=2\sqrt{865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{865}}{2*-16}=\frac{-18-2\sqrt{865}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{865}}{2*-16}=\frac{-18+2\sqrt{865}}{-32}
$